1. p - 19
2. 12 + 5c
3. (n/6) - 1
4. 9 ( t + 3)
5. 12 ( 15 - d)
6. 15
7. 25
8. 324
9. -144
10. -(1/64)
11. 12.5
12. -22
13. 350
14. 28
15. -700
16. sqrt 1.1 is an irrational
-1 is an integer and a rational
1/2 is a rational
least -1, 1/2, sqrt 1.1
17. about 11
18. additive identity
19. yes, they are equivalent because the fraction simplifies to 4m
20. yes, it's a solution
21. no, it isn't a solution
22. least -1.75, -(5/4), -(1/4), 3/4 greatest
23. -14
24. -7
25. 25
26. -2xy^2
27. 14
28. 1+0.5p
29. work will vary ( I solved for method 1 and used a table for the second method )
30. original = 22. Put () around 2 + 9 and change minus to plus
31. zero is the diffence. Whole numbers have a zerobut natural numbers do not.
32. if you count negatives, odd numbers of negatives will produce a negative answer.
2. 12 + 5c
3. (n/6) - 1
4. 9 ( t + 3)
5. 12 ( 15 - d)
6. 15
7. 25
8. 324
9. -144
10. -(1/64)
11. 12.5
12. -22
13. 350
14. 28
15. -700
16. sqrt 1.1 is an irrational
-1 is an integer and a rational
1/2 is a rational
least -1, 1/2, sqrt 1.1
17. about 11
18. additive identity
19. yes, they are equivalent because the fraction simplifies to 4m
20. yes, it's a solution
21. no, it isn't a solution
22. least -1.75, -(5/4), -(1/4), 3/4 greatest
23. -14
24. -7
25. 25
26. -2xy^2
27. 14
28. 1+0.5p
29. work will vary ( I solved for method 1 and used a table for the second method )
30. original = 22. Put () around 2 + 9 and change minus to plus
31. zero is the diffence. Whole numbers have a zerobut natural numbers do not.
32. if you count negatives, odd numbers of negatives will produce a negative answer.